Base | Representation |
---|---|
bin | 110100001010100011… |
… | …0010101010011000101 |
3 | 101201011002021200211012 |
4 | 1220111012111103011 |
5 | 3313410410200313 |
6 | 123243540252005 |
7 | 11044015622351 |
oct | 1502506252305 |
9 | 351132250735 |
10 | 112023131333 |
11 | 43566156683 |
12 | 198643a1005 |
13 | a7436b2a39 |
14 | 55c9b80461 |
15 | 2da9a28da8 |
hex | 1a151954c5 |
112023131333 has 2 divisors, whose sum is σ = 112023131334. Its totient is φ = 112023131332.
The previous prime is 112023131329. The next prime is 112023131357. The reversal of 112023131333 is 333131320211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107871519844 + 4151611489 = 328438^2 + 64433^2 .
It is a cyclic number.
It is not a de Polignac number, because 112023131333 - 22 = 112023131329 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112023131299 and 112023131308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112023136333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56011565666 + 56011565667.
It is an arithmetic number, because the mean of its divisors is an integer number (56011565667).
Almost surely, 2112023131333 is an apocalyptic number.
It is an amenable number.
112023131333 is a deficient number, since it is larger than the sum of its proper divisors (1).
112023131333 is an equidigital number, since it uses as much as digits as its factorization.
112023131333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 112023131333 its reverse (333131320211), we get a palindrome (445154451544).
The spelling of 112023131333 in words is "one hundred twelve billion, twenty-three million, one hundred thirty-one thousand, three hundred thirty-three".
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