Search a number
-
+
11204013311132 = 222801003327783
BaseRepresentation
bin1010001100001010001100…
…1110111100010010011100
31110200002111221200200200212
42203002203032330102130
52432031304401424012
635455015212511552
72234314615544015
oct243024316742234
943602457620625
1011204013311132
11362a660476174
12130b4b547b5b8
136336c3045635
142aa3c467400c
15146697132b22
hexa30a33bc49c

11204013311132 has 6 divisors (see below), whose sum is σ = 19607023294488. Its totient is φ = 5602006655564.

The previous prime is 11204013311017. The next prime is 11204013311159. The reversal of 11204013311132 is 23111331040211.

It is a junction number, because it is equal to n+sod(n) for n = 11204013311098 and 11204013311107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1400501663888 + ... + 1400501663895.

It is an arithmetic number, because the mean of its divisors is an integer number (3267837215748).

Almost surely, 211204013311132 is an apocalyptic number.

It is an amenable number.

11204013311132 is a deficient number, since it is larger than the sum of its proper divisors (8403009983356).

11204013311132 is a wasteful number, since it uses less digits than its factorization.

11204013311132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2801003327787 (or 2801003327785 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 11204013311132 its reverse (23111331040211), we get a palindrome (34315344351343).

The spelling of 11204013311132 in words is "eleven trillion, two hundred four billion, thirteen million, three hundred eleven thousand, one hundred thirty-two".

Divisors: 1 2 4 2801003327783 5602006655566 11204013311132