Base | Representation |
---|---|
bin | 1010001100001010010100… |
… | …0100001011111101111111 |
3 | 1110200002121002112012021222 |
4 | 2203002211010023331333 |
5 | 2432031340233434312 |
6 | 35455022231343555 |
7 | 2234315441023445 |
oct | 243024504137577 |
9 | 43602532465258 |
10 | 11204044046207 |
11 | 362a676858961 |
12 | 130b503821bbb |
13 | 6336c951707c |
14 | 2aa3c8794b95 |
15 | 146699ba4672 |
hex | a30a510bf7f |
11204044046207 has 2 divisors, whose sum is σ = 11204044046208. Its totient is φ = 11204044046206.
The previous prime is 11204044046191. The next prime is 11204044046233. The reversal of 11204044046207 is 70264044040211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11204044046207 - 24 = 11204044046191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11204044046257) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5602022023103 + 5602022023104.
It is an arithmetic number, because the mean of its divisors is an integer number (5602022023104).
Almost surely, 211204044046207 is an apocalyptic number.
11204044046207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11204044046207 is an equidigital number, since it uses as much as digits as its factorization.
11204044046207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43008, while the sum is 35.
Adding to 11204044046207 its reverse (70264044040211), we get a palindrome (81468088086418).
The spelling of 11204044046207 in words is "eleven trillion, two hundred four billion, forty-four million, forty-six thousand, two hundred seven".
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