1120431133 has 4 divisors (see below), whose sum is σ = 1130902560. Its totient is φ = 1109959708.

The previous prime is 1120431127. The next prime is 1120431139. The reversal of 1120431133 is 3311340211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3311340211 = 7937 ⋅417203.

It is an interprime number because it is at equal distance from previous prime (1120431127) and next prime (1120431139).

It is a cyclic number.

It is not a de Polignac number, because 1120431133 - 2⁵ = 1120431101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1120431133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1120431139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5235553 + ... + 5235766.

It is an arithmetic number, because the mean of its divisors is an integer number (282725640).

Almost surely, 2^1120431133 is an apocalyptic number.

It is an amenable number.

1120431133 is a deficient number, since it is larger than the sum of its proper divisors (10471427).

1120431133 is a wasteful number, since it uses less digits than its factorization.

1120431133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10471426.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1120431133 is about 33472.8417228057. The cubic root of 1120431133 is about 1038.6320565828.

Adding to 1120431133 its reverse (3311340211), we get a palindrome (4431771344).

The spelling of 1120431133 in words is "one billion, one hundred twenty million, four hundred thirty-one thousand, one hundred thirty-three".