11204331404413 has 4 divisors (see below), whose sum is σ = 12804950176480. Its totient is φ = 9603712632348.

The previous prime is 11204331404381. The next prime is 11204331404429. The reversal of 11204331404413 is 31440413340211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11204331404413 - 2⁵ = 11204331404381 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11204331401413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 800309386023 + ... + 800309386036.

It is an arithmetic number, because the mean of its divisors is an integer number (3201237544120).

Almost surely, 2^{11204331404413} is an apocalyptic number.

It is an amenable number.

11204331404413 is a deficient number, since it is larger than the sum of its proper divisors (1600618772067).

11204331404413 is an equidigital number, since it uses as much as digits as its factorization.

11204331404413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1600618772066.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 11204331404413 its reverse (31440413340211), we get a palindrome (42644744744624).

The spelling of 11204331404413 in words is "eleven trillion, two hundred four billion, three hundred thirty-one million, four hundred four thousand, four hundred thirteen".