Base | Representation |
---|---|
bin | 10000010011100101100… |
… | …100110111000111001110 |
3 | 10222010022120121112012211 |
4 | 100103211210313013032 |
5 | 121324333021023400 |
6 | 2214434224221034 |
7 | 143646050361562 |
oct | 20234544670716 |
9 | 3863276545184 |
10 | 1120543142350 |
11 | 3a2246433995 |
12 | 16120376a77a |
13 | 81888b61bc8 |
14 | 3c33d9756a2 |
15 | 1e234257dba |
hex | 104e59371ce |
1120543142350 has 24 divisors (see below), whose sum is σ = 2119535847720. Its totient is φ = 440620353120.
The previous prime is 1120543142273. The next prime is 1120543142353. The reversal of 1120543142350 is 532413450211.
It is a super-2 number, since 2×11205431423502 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1120543142353) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 189919617 + ... + 189925516.
It is an arithmetic number, because the mean of its divisors is an integer number (88313993655).
Almost surely, 21120543142350 is an apocalyptic number.
1120543142350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1120543142350 is a deficient number, since it is larger than the sum of its proper divisors (998992705370).
1120543142350 is a wasteful number, since it uses less digits than its factorization.
1120543142350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 379845204 (or 379845199 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1120543142350 its reverse (532413450211), we get a palindrome (1652956592561).
The spelling of 1120543142350 in words is "one trillion, one hundred twenty billion, five hundred forty-three million, one hundred forty-two thousand, three hundred fifty".
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