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11205432013045 = 513191699079911
BaseRepresentation
bin1010001100001111011111…
…0010110111000011110101
31110200020011211020012212011
42203003313302313003311
52432042211043404140
635455412052324221
72234365023401134
oct243036762670365
943606154205764
1011205432013045
113630219278996
12130b830613671
1363388ac4171a
142aa4bac5391b
1514672b96dcea
hexa30f7cb70f5

11205432013045 has 8 divisors (see below), whose sum is σ = 13456712903040. Its totient is φ = 8957549285520.

The previous prime is 11205432013033. The next prime is 11205432013051. The reversal of 11205432013045 is 54031023450211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11205432013045 - 27 = 11205432012917 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11205432012998 and 11205432013016.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 849533361 + ... + 849546550.

It is an arithmetic number, because the mean of its divisors is an integer number (1682089112880).

Almost surely, 211205432013045 is an apocalyptic number.

It is an amenable number.

11205432013045 is a deficient number, since it is larger than the sum of its proper divisors (2251280889995).

11205432013045 is a wasteful number, since it uses less digits than its factorization.

11205432013045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1699081235.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 11205432013045 its reverse (54031023450211), we get a palindrome (65236455463256).

The spelling of 11205432013045 in words is "eleven trillion, two hundred five billion, four hundred thirty-two million, thirteen thousand, forty-five".

Divisors: 1 5 1319 6595 1699079911 8495399555 2241086402609 11205432013045