Base | Representation |
---|---|
bin | 1010001100001111011111… |
… | …0010110111000011110101 |
3 | 1110200020011211020012212011 |
4 | 2203003313302313003311 |
5 | 2432042211043404140 |
6 | 35455412052324221 |
7 | 2234365023401134 |
oct | 243036762670365 |
9 | 43606154205764 |
10 | 11205432013045 |
11 | 3630219278996 |
12 | 130b830613671 |
13 | 63388ac4171a |
14 | 2aa4bac5391b |
15 | 14672b96dcea |
hex | a30f7cb70f5 |
11205432013045 has 8 divisors (see below), whose sum is σ = 13456712903040. Its totient is φ = 8957549285520.
The previous prime is 11205432013033. The next prime is 11205432013051. The reversal of 11205432013045 is 54031023450211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11205432013045 - 27 = 11205432012917 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11205432012998 and 11205432013016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 849533361 + ... + 849546550.
It is an arithmetic number, because the mean of its divisors is an integer number (1682089112880).
Almost surely, 211205432013045 is an apocalyptic number.
It is an amenable number.
11205432013045 is a deficient number, since it is larger than the sum of its proper divisors (2251280889995).
11205432013045 is a wasteful number, since it uses less digits than its factorization.
11205432013045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1699081235.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 11205432013045 its reverse (54031023450211), we get a palindrome (65236455463256).
The spelling of 11205432013045 in words is "eleven trillion, two hundred five billion, four hundred thirty-two million, thirteen thousand, forty-five".
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