Base | Representation |
---|---|
bin | 1010001100100000100000… |
… | …0100011011001010011111 |
3 | 1110200122222011202000112122 |
4 | 2203020020010123022133 |
5 | 2432131040001121002 |
6 | 35501445232453155 |
7 | 2234616151665056 |
oct | 243101004331237 |
9 | 43618864660478 |
10 | 11210000020127 |
11 | 3632152849257 |
12 | 13106a63aa1bb |
13 | 6341384398ac |
14 | 2aa7d17c339d |
15 | 1468e79e26a2 |
hex | a320811b29f |
11210000020127 has 2 divisors, whose sum is σ = 11210000020128. Its totient is φ = 11210000020126.
The previous prime is 11210000020069. The next prime is 11210000020133. The reversal of 11210000020127 is 72102000001211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11210000020127 - 234 = 11192820150943 is a prime.
It is a super-2 number, since 2×112100000201272 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11210020020127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605000010063 + 5605000010064.
It is an arithmetic number, because the mean of its divisors is an integer number (5605000010064).
Almost surely, 211210000020127 is an apocalyptic number.
11210000020127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210000020127 is an equidigital number, since it uses as much as digits as its factorization.
11210000020127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 11210000020127 its reverse (72102000001211), we get a palindrome (83312000021338).
The spelling of 11210000020127 in words is "eleven trillion, two hundred ten billion, twenty thousand, one hundred twenty-seven".
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