Base | Representation |
---|---|
bin | 10100111000010101… |
… | …10000011100001111 |
3 | 1001221020121000021111 |
4 | 22130022300130033 |
5 | 140424230001033 |
6 | 5052205112451 |
7 | 544536300106 |
oct | 123412603417 |
9 | 31836530244 |
10 | 11210000143 |
11 | 4832831031 |
12 | 220a258727 |
13 | 10985a35a4 |
14 | 784b3703d |
15 | 4592217cd |
hex | 29c2b070f |
11210000143 has 2 divisors, whose sum is σ = 11210000144. Its totient is φ = 11210000142.
The previous prime is 11210000119. The next prime is 11210000173. The reversal of 11210000143 is 34100001211.
It is a weak prime.
It is an emirp because it is prime and its reverse (34100001211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11210000143 - 221 = 11207902991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11210000173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605000071 + 5605000072.
It is an arithmetic number, because the mean of its divisors is an integer number (5605000072).
Almost surely, 211210000143 is an apocalyptic number.
11210000143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210000143 is an equidigital number, since it uses as much as digits as its factorization.
11210000143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 11210000143 its reverse (34100001211), we get a palindrome (45310001354).
The spelling of 11210000143 in words is "eleven billion, two hundred ten million, one hundred forty-three", and thus it is an aban number.
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