Search a number
-
+
112100100100133 is a prime number
BaseRepresentation
bin11001011111010001010110…
…101001010101000000100101
3112200220122221201101120220012
4121133101112221111000211
5104143122001111201013
61034230024113220005
732416651661033345
oct3137212651250045
9480818851346805
10112100100100133
113279a427076862
12106a5900861605
134a71cbccc24c2
141d97960c6ad25
15ce5eaa5ee1a8
hex65f456a55025

112100100100133 has 2 divisors, whose sum is σ = 112100100100134. Its totient is φ = 112100100100132.

The previous prime is 112100100100091. The next prime is 112100100100181. The reversal of 112100100100133 is 331001001001211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111881242676449 + 218857423684 = 10577393^2 + 467822^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112100100100133 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112100100109133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050050050066 + 56050050050067.

It is an arithmetic number, because the mean of its divisors is an integer number (56050050050067).

Almost surely, 2112100100100133 is an apocalyptic number.

It is an amenable number.

112100100100133 is a deficient number, since it is larger than the sum of its proper divisors (1).

112100100100133 is an equidigital number, since it uses as much as digits as its factorization.

112100100100133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 112100100100133 its reverse (331001001001211), we get a palindrome (443101101101344).

The spelling of 112100100100133 in words is "one hundred twelve trillion, one hundred billion, one hundred million, one hundred thousand, one hundred thirty-three".