Base | Representation |
---|---|
bin | 10000010100000000110… |
… | …111011101000000101111 |
3 | 10222011111111011011012212 |
4 | 100110000313131000233 |
5 | 121331302224013012 |
6 | 2214551501521035 |
7 | 143663310201506 |
oct | 20240067350057 |
9 | 3864444134185 |
10 | 1121001001007 |
11 | 3a2460927978 |
12 | 161310b7317b |
13 | 8192c9808a4 |
14 | 3c3846bb83d |
15 | 1e25e549b22 |
hex | 10500ddd02f |
1121001001007 has 2 divisors, whose sum is σ = 1121001001008. Its totient is φ = 1121001001006.
The previous prime is 1121001000991. The next prime is 1121001001013. The reversal of 1121001001007 is 7001001001211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1121001001007 - 24 = 1121001000991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1121001000982 and 1121001001000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121001001037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560500500503 + 560500500504.
It is an arithmetic number, because the mean of its divisors is an integer number (560500500504).
Almost surely, 21121001001007 is an apocalyptic number.
1121001001007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121001001007 is an equidigital number, since it uses as much as digits as its factorization.
1121001001007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 1121001001007 its reverse (7001001001211), we get a palindrome (8122002002218).
The spelling of 1121001001007 in words is "one trillion, one hundred twenty-one billion, one million, one thousand, seven".
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