Base | Representation |
---|---|
bin | 11001011111010010010010… |
… | …010111010100001011100111 |
3 | 112200220202112112122221101012 |
4 | 121133102102113110023213 |
5 | 104143131024103323421 |
6 | 1034230311343452435 |
7 | 32420015545113533 |
oct | 3137222227241347 |
9 | 480822475587335 |
10 | 112101102011111 |
11 | 3279a8a0685364 |
12 | 106a5b402b711b |
13 | 4a7211c74b435 |
14 | 1d97a17d54bc3 |
15 | ce601855b95b |
hex | 65f4925d42e7 |
112101102011111 has 2 divisors, whose sum is σ = 112101102011112. Its totient is φ = 112101102011110.
The previous prime is 112101102011057. The next prime is 112101102011117. The reversal of 112101102011111 is 111110201101211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112101102011111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112101102011117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050551005555 + 56050551005556.
It is an arithmetic number, because the mean of its divisors is an integer number (56050551005556).
Almost surely, 2112101102011111 is an apocalyptic number.
112101102011111 is a deficient number, since it is larger than the sum of its proper divisors (1).
112101102011111 is an equidigital number, since it uses as much as digits as its factorization.
112101102011111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 14.
Adding to 112101102011111 its reverse (111110201101211), we get a palindrome (223211303112322).
The spelling of 112101102011111 in words is "one hundred twelve trillion, one hundred one billion, one hundred two million, eleven thousand, one hundred eleven".
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