Base | Representation |
---|---|
bin | 110100001100110111… |
… | …1110011000101100101 |
3 | 101201100112000102121022 |
4 | 1220121233303011211 |
5 | 3314040341010432 |
6 | 123255403500525 |
7 | 11045653466633 |
oct | 1503157630545 |
9 | 351315012538 |
10 | 112101110117 |
11 | 435a6177257 |
12 | 19886527745 |
13 | a7568b6129 |
14 | 55d627c353 |
15 | 2db17cdb12 |
hex | 1a19bf3165 |
112101110117 has 2 divisors, whose sum is σ = 112101110118. Its totient is φ = 112101110116.
The previous prime is 112101110089. The next prime is 112101110131. The reversal of 112101110117 is 711011101211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96726598081 + 15374512036 = 311009^2 + 123994^2 .
It is a cyclic number.
It is not a de Polignac number, because 112101110117 - 210 = 112101109093 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112101110095 and 112101110104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112101115117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050555058 + 56050555059.
It is an arithmetic number, because the mean of its divisors is an integer number (56050555059).
Almost surely, 2112101110117 is an apocalyptic number.
It is an amenable number.
112101110117 is a deficient number, since it is larger than the sum of its proper divisors (1).
112101110117 is an equidigital number, since it uses as much as digits as its factorization.
112101110117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 17.
Adding to 112101110117 its reverse (711011101211), we get a palindrome (823112211328).
The spelling of 112101110117 in words is "one hundred twelve billion, one hundred one million, one hundred ten thousand, one hundred seventeen".
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