Base | Representation |
---|---|
bin | 10000010100000001011… |
… | …110110101000011111100 |
3 | 10222011112012120120111210 |
4 | 100110001132311003330 |
5 | 121331312344320012 |
6 | 2214552511044420 |
7 | 143663464012251 |
oct | 20240136650374 |
9 | 3864465516453 |
10 | 1121011323132 |
11 | 3a2466738058 |
12 | 161314510710 |
13 | 81931b55c5c |
14 | 3c385c07428 |
15 | 1e2603d823c |
hex | 105017b50fc |
1121011323132 has 12 divisors (see below), whose sum is σ = 2615693087336. Its totient is φ = 373670441040.
The previous prime is 1121011323119. The next prime is 1121011323169. The reversal of 1121011323132 is 2313231101211.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 1121011323099 and 1121011323108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46708805119 + ... + 46708805142.
Almost surely, 21121011323132 is an apocalyptic number.
1121011323132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1121011323132 is an abundant number, since it is smaller than the sum of its proper divisors (1494681764204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1121011323132 is a wasteful number, since it uses less digits than its factorization.
1121011323132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93417610268 (or 93417610266 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1121011323132 its reverse (2313231101211), we get a palindrome (3434242424343).
The spelling of 1121011323132 in words is "one trillion, one hundred twenty-one billion, eleven million, three hundred twenty-three thousand, one hundred thirty-two".
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