Base | Representation |
---|---|
bin | 10000010100000001100… |
… | …001011010010110000011 |
3 | 10222011112020211222011211 |
4 | 100110001201122112003 |
5 | 121331313033001011 |
6 | 2214552533350551 |
7 | 143663502532102 |
oct | 20240141322603 |
9 | 3864466758154 |
10 | 1121012000131 |
11 | 3a246705a761 |
12 | 161314798457 |
13 | 8193203214a |
14 | 3c385d42039 |
15 | 1e2604bdb21 |
hex | 1050185a583 |
1121012000131 has 2 divisors, whose sum is σ = 1121012000132. Its totient is φ = 1121012000130.
The previous prime is 1121012000111. The next prime is 1121012000159. The reversal of 1121012000131 is 1310002101211.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (1310002101211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1121012000131 - 25 = 1121012000099 is a prime.
It is a super-2 number, since 2×11210120001312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1121012000111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560506000065 + 560506000066.
It is an arithmetic number, because the mean of its divisors is an integer number (560506000066).
Almost surely, 21121012000131 is an apocalyptic number.
1121012000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121012000131 is an equidigital number, since it uses as much as digits as its factorization.
1121012000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 1121012000131 its reverse (1310002101211), we get a palindrome (2431014101342).
The spelling of 1121012000131 in words is "one trillion, one hundred twenty-one billion, twelve million, one hundred thirty-one", and thus it is an aban number.
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