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112103113 is a prime number
BaseRepresentation
bin1101010111010…
…00111011001001
321210221102120011
412223220323021
5212144244423
615042431521
72530601143
oct653507311
9253842504
10112103113
1158308801
12316625a1
131a2c0705
1410c61c93
159c95b0d
hex6ae8ec9

112103113 has 2 divisors, whose sum is σ = 112103114. Its totient is φ = 112103112.

The previous prime is 112103111. The next prime is 112103137. The reversal of 112103113 is 311301211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111450249 + 652864 = 10557^2 + 808^2 .

It is a cyclic number.

It is not a de Polignac number, because 112103113 - 21 = 112103111 is a prime.

Together with 112103111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 112103093 and 112103102.

It is not a weakly prime, because it can be changed into another prime (112103111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051556 + 56051557.

It is an arithmetic number, because the mean of its divisors is an integer number (56051557).

Almost surely, 2112103113 is an apocalyptic number.

It is an amenable number.

112103113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112103113 is an equidigital number, since it uses as much as digits as its factorization.

112103113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 112103113 is about 10587.8757548434. The cubic root of 112103113 is about 482.1763342472.

Adding to 112103113 its reverse (311301211), we get a palindrome (423404324).

The spelling of 112103113 in words is "one hundred twelve million, one hundred three thousand, one hundred thirteen".