Base | Representation |
---|---|
bin | 10100111000011000… |
… | …00001000011011010 |
3 | 1001221021012210012122 |
4 | 22130030001003122 |
5 | 140424321032310 |
6 | 5052220141242 |
7 | 544542143543 |
oct | 123414010332 |
9 | 31837183178 |
10 | 11210330330 |
11 | 4832a37111 |
12 | 220a397822 |
13 | 109868a974 |
14 | 784bc14ca |
15 | 459289555 |
hex | 29c3010da |
11210330330 has 32 divisors (see below), whose sum is σ = 20267133120. Its totient is φ = 4464503680.
The previous prime is 11210330311. The next prime is 11210330347. The reversal of 11210330330 is 3303301211.
11210330330 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×112103303302 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11210330299 and 11210330308.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2290526 + ... + 2295414.
It is an arithmetic number, because the mean of its divisors is an integer number (633347910).
Almost surely, 211210330330 is an apocalyptic number.
11210330330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11210330330 is a deficient number, since it is larger than the sum of its proper divisors (9056802790).
11210330330 is a wasteful number, since it uses less digits than its factorization.
11210330330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5854.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 11210330330 its reverse (3303301211), we get a palindrome (14513631541).
The spelling of 11210330330 in words is "eleven billion, two hundred ten million, three hundred thirty thousand, three hundred thirty".
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