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112110000133 is a prime number
BaseRepresentation
bin110100001101001000…
…1101101100000000101
3101201101010202002102011
41220122101231200011
53314100130001013
6123300322214221
711046122164225
oct1503221554005
9351333662364
10112110000133
114360019947a
12198894b4371
13a7586a96b1
1455d7514085
152db2487c3d
hex1a1a46d805

112110000133 has 2 divisors, whose sum is σ = 112110000134. Its totient is φ = 112110000132.

The previous prime is 112110000103. The next prime is 112110000199. The reversal of 112110000133 is 331000011211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97280362404 + 14829637729 = 311898^2 + 121777^2 .

It is an emirp because it is prime and its reverse (331000011211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112110000133 - 233 = 103520065541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112110000103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055000066 + 56055000067.

It is an arithmetic number, because the mean of its divisors is an integer number (56055000067).

Almost surely, 2112110000133 is an apocalyptic number.

It is an amenable number.

112110000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

112110000133 is an equidigital number, since it uses as much as digits as its factorization.

112110000133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 112110000133 its reverse (331000011211), we get a palindrome (443110011344).

The spelling of 112110000133 in words is "one hundred twelve billion, one hundred ten million, one hundred thirty-three", and thus it is an aban number.