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1121101121011 is a prime number
BaseRepresentation
bin10000010100000110110…
…101011000010111110011
310222011202110112210001011
4100110012311120113303
5121332003341333021
62215005435451351
7143665634203534
oct20240665302763
93864673483034
101121101121011
113a25023a0583
1216133a5b6b57
1381947636bb1
143c393b0068b
151e268224de1
hex10506d585f3

1121101121011 has 2 divisors, whose sum is σ = 1121101121012. Its totient is φ = 1121101121010.

The previous prime is 1121101120991. The next prime is 1121101121089. The reversal of 1121101121011 is 1101211011211.

It is a weak prime.

It is an emirp because it is prime and its reverse (1101211011211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1121101121011 - 215 = 1121101088243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1121101120982 and 1121101121000.

It is not a weakly prime, because it can be changed into another prime (1121101121711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560550560505 + 560550560506.

It is an arithmetic number, because the mean of its divisors is an integer number (560550560506).

Almost surely, 21121101121011 is an apocalyptic number.

1121101121011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121101121011 is an equidigital number, since it uses as much as digits as its factorization.

1121101121011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 1121101121011 its reverse (1101211011211), we get a palindrome (2222312132222).

The spelling of 1121101121011 in words is "one trillion, one hundred twenty-one billion, one hundred one million, one hundred twenty-one thousand, eleven".