1121101411 has 2 divisors, whose sum is σ = 1121101412. Its totient is φ = 1121101410.

The previous prime is 1121101379. The next prime is 1121101427. The reversal of 1121101411 is 1141011211.

It is a strong prime.

It is an emirp because it is prime and its reverse (1141011211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1121101411 - 2⁵ = 1121101379 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1121101391 and 1121101400.

It is not a weakly prime, because it can be changed into another prime (1121101451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560550705 + 560550706.

It is an arithmetic number, because the mean of its divisors is an integer number (560550706).

Almost surely, 2^1121101411 is an apocalyptic number.

1121101411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121101411 is an equidigital number, since it uses as much as digits as its factorization.

1121101411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

The square root of 1121101411 is about 33482.8524919846. The cubic root of 1121101411 is about 1038.8391296814.

Adding to 1121101411 its reverse (1141011211), we get a palindrome (2262112622).

The spelling of 1121101411 in words is "one billion, one hundred twenty-one million, one hundred one thousand, four hundred eleven".