Base | Representation |
---|---|
bin | 1010001100100100100110… |
… | …1000111110101110011011 |
3 | 1110200202210211202222121212 |
4 | 2203021021220332232123 |
5 | 2432140313112401021 |
6 | 35502150331453335 |
7 | 2234655340464146 |
oct | 243111150765633 |
9 | 43622724688555 |
10 | 11211100122011 |
11 | 3632667823069 |
12 | 13109528b724b |
13 | 634282324a5a |
14 | 2aa89794b05d |
15 | 14695e39885b |
hex | a3249a3eb9b |
11211100122011 has 2 divisors, whose sum is σ = 11211100122012. Its totient is φ = 11211100122010.
The previous prime is 11211100121999. The next prime is 11211100122029. The reversal of 11211100122011 is 11022100111211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11211100122011 is a prime.
It is not a weakly prime, because it can be changed into another prime (11211100122611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605550061005 + 5605550061006.
It is an arithmetic number, because the mean of its divisors is an integer number (5605550061006).
Almost surely, 211211100122011 is an apocalyptic number.
11211100122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11211100122011 is an equidigital number, since it uses as much as digits as its factorization.
11211100122011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 11211100122011 its reverse (11022100111211), we get a palindrome (22233200233222).
The spelling of 11211100122011 in words is "eleven trillion, two hundred eleven billion, one hundred million, one hundred twenty-two thousand, eleven".
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