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112111102103 = 71113111999103
BaseRepresentation
bin110100001101001010…
…1111010100010010111
3101201101012211002000212
41220122111322202113
53314100420231403
6123300402000035
711046134434040
oct1503225724227
9351335732025
10112111102103
11436008813a0
121988994601b
13a7589a4150
1455d771d8c7
152db26044d8
hex1a1a57a897

112111102103 has 16 divisors (see below), whose sum is σ = 150526795776. Its totient is φ = 80639353440.

The previous prime is 112111102093. The next prime is 112111102109. The reversal of 112111102103 is 301201111211.

It is a cyclic number.

It is not a de Polignac number, because 112111102103 - 28 = 112111101847 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112111102109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55998551 + ... + 56000552.

It is an arithmetic number, because the mean of its divisors is an integer number (9407924736).

Almost surely, 2112111102103 is an apocalyptic number.

112111102103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

112111102103 is a deficient number, since it is larger than the sum of its proper divisors (38415693673).

112111102103 is a wasteful number, since it uses less digits than its factorization.

112111102103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111999134.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 112111102103 its reverse (301201111211), we get a palindrome (413312213314).

The spelling of 112111102103 in words is "one hundred twelve billion, one hundred eleven million, one hundred two thousand, one hundred three".

Divisors: 1 7 11 13 77 91 143 1001 111999103 783993721 1231990133 1455988339 8623930931 10191918373 16015871729 112111102103