Base | Representation |
---|---|
bin | 11001011111011100011101… |
… | …010000001010010100000111 |
3 | 112200221210201120202002201011 |
4 | 121133130131100022110013 |
5 | 104143320410124301203 |
6 | 1034235315115143051 |
7 | 32420553264266155 |
oct | 3137343520122407 |
9 | 480853646662634 |
10 | 112112022103303 |
11 | 327a44947a5242 |
12 | 106a8089444a87 |
13 | 4a7316cc48651 |
14 | 1d983723843d5 |
15 | ce64570b476d |
hex | 65f71d40a507 |
112112022103303 has 2 divisors, whose sum is σ = 112112022103304. Its totient is φ = 112112022103302.
The previous prime is 112112022103297. The next prime is 112112022103337. The reversal of 112112022103303 is 303301220211211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112112022103303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112112022203303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056011051651 + 56056011051652.
It is an arithmetic number, because the mean of its divisors is an integer number (56056011051652).
Almost surely, 2112112022103303 is an apocalyptic number.
112112022103303 is a deficient number, since it is larger than the sum of its proper divisors (1).
112112022103303 is an equidigital number, since it uses as much as digits as its factorization.
112112022103303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 112112022103303 its reverse (303301220211211), we get a palindrome (415413242314514).
The spelling of 112112022103303 in words is "one hundred twelve trillion, one hundred twelve billion, twenty-two million, one hundred three thousand, three hundred three".
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