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1121121300103 = 7431371601359
BaseRepresentation
bin10000010100001000000…
…010010110111010000111
310222011210212111222112221
4100110020002112322013
5121332024023100403
62215011440153211
7143666300546650
oct20241002267207
93864725458487
101121121300103
113a2512823412
12161345308807
138194b88099c
143c396674527
151e269daddbd
hex10508096e87

1121121300103 has 8 divisors (see below), whose sum is σ = 1284254300160. Its totient is φ = 958731503640.

The previous prime is 1121121300083. The next prime is 1121121300109. The reversal of 1121121300103 is 3010031211211.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1121121300103 - 25 = 1121121300071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1121121300109) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185797663 + ... + 185803696.

It is an arithmetic number, because the mean of its divisors is an integer number (160531787520).

Almost surely, 21121121300103 is an apocalyptic number.

1121121300103 is a deficient number, since it is larger than the sum of its proper divisors (163133000057).

1121121300103 is an equidigital number, since it uses as much as digits as its factorization.

1121121300103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 371601797.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 1121121300103 its reverse (3010031211211), we get a palindrome (4131152511314).

The spelling of 1121121300103 in words is "one trillion, one hundred twenty-one billion, one hundred twenty-one million, three hundred thousand, one hundred three".

Divisors: 1 7 431 3017 371601359 2601209513 160160185729 1121121300103