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112112231302 = 256056115651
BaseRepresentation
bin110100001101001101…
…0001110001110000110
3101201101021221110000001
41220122122032032012
53314101212400202
6123300442111514
711046150146131
oct1503232161606
9351337843001
10112112231302
1143601482815
121988a1ab59a
13a758cab106
1455d7935218
152db2778d87
hex1a1a68e386

112112231302 has 4 divisors (see below), whose sum is σ = 168168346956. Its totient is φ = 56056115650.

The previous prime is 112112231293. The next prime is 112112231323. The reversal of 112112231302 is 203132211211.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 203132211211 = 331613692481.

It is a self number, because there is not a number n which added to its sum of digits gives 112112231302.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28028057824 + ... + 28028057827.

It is an arithmetic number, because the mean of its divisors is an integer number (42042086739).

Almost surely, 2112112231302 is an apocalyptic number.

112112231302 is a deficient number, since it is larger than the sum of its proper divisors (56056115654).

112112231302 is an equidigital number, since it uses as much as digits as its factorization.

112112231302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56056115653.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 112112231302 its reverse (203132211211), we get a palindrome (315244442513).

The spelling of 112112231302 in words is "one hundred twelve billion, one hundred twelve million, two hundred thirty-one thousand, three hundred two".

Divisors: 1 2 56056115651 112112231302