| Base | Representation |
|---|---|
| bin | 11001011111011101011111… |
| … | …010111011100101110110000 |
| 3 | 112200221220120212220122020200 |
| 4 | 121133131133113130232300 |
| 5 | 104143330143103410000 |
| 6 | 1034240021141235200 |
| 7 | 32420622623346012 |
| oct | 3137353727345660 |
| 9 | 480856525818220 |
| 10 | 112113131310000 |
| 11 | 327a4a03928697 |
| 12 | 106a8338a02b00 |
| 13 | 4a732b89a0a82 |
| 14 | 1d984397dc1b2 |
| 15 | ce64be668500 |
| hex | 65f75f5dcbb0 |
112113131310000 has 1200 divisors, whose sum is σ = 423243019879680. Its totient is φ = 27621285120000.
The previous prime is 112113131309987. The next prime is 112113131310013. The reversal of 112113131310000 is 13131311211.
112113131310000 is a `hidden beast` number, since 1 + 121 + 131 + 313 + 100 + 0 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (112113131309987) and next prime (112113131310013).
It is a tau number, because it is divible by the number of its divisors (1200).
It is a super-2 number, since 2×1121131313100002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 10646004735 + ... + 10646015265.
Almost surely, 2112113131310000 is an apocalyptic number.
112113131310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112113131310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (211621509939840).
112113131310000 is an abundant number, since it is smaller than the sum of its proper divisors (311129888569680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112113131310000 is a wasteful number, since it uses less digits than its factorization.
112113131310000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10764 (or 10740 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 112113131310000 its reverse (13131311211), we get a palindrome (112126262621211).
The spelling of 112113131310000 in words is "one hundred twelve trillion, one hundred thirteen billion, one hundred thirty-one million, three hundred ten thousand".
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