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11212000111212 = 223991942818711
BaseRepresentation
bin1010001100100111111101…
…0010001010101001101100
31110200212010120021011201020
42203021333102022221230
52432144134012024322
635502415521414140
72235016546326315
oct243117722125154
943625116234636
1011212000111212
113632a8984829a
121310b6419a350
13634396916544
142aa9412a360c
151469b33c205c
hexa327f48aa6c

11212000111212 has 24 divisors (see below), whose sum is σ = 26187732544512. Its totient is φ = 3733562091600.

The previous prime is 11212000111201. The next prime is 11212000111223. The reversal of 11212000111212 is 21211100021211.

It is a happy number.

11212000111212 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11212000111201) and next prime (11212000111223).

It is a junction number, because it is equal to n+sod(n) for n = 11212000111191 and 11212000111200.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 471397464 + ... + 471421247.

It is an arithmetic number, because the mean of its divisors is an integer number (1091155522688).

Almost surely, 211212000111212 is an apocalyptic number.

11212000111212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11212000111212 is an abundant number, since it is smaller than the sum of its proper divisors (14975732433300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11212000111212 is a wasteful number, since it uses less digits than its factorization.

11212000111212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 942819709 (or 942819707 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 11212000111212 its reverse (21211100021211), we get a palindrome (32423100132423).

Subtracting 11212000111212 from its reverse (21211100021211), we obtain a palindrome (9999099909999).

The spelling of 11212000111212 in words is "eleven trillion, two hundred twelve billion, one hundred eleven thousand, two hundred twelve".

Divisors: 1 2 3 4 6 12 991 1982 2973 3964 5946 11892 942818711 1885637422 2828456133 3771274844 5656912266 11313824532 934333342601 1868666685202 2803000027803 3737333370404 5606000055606 11212000111212