Base | Representation |
---|---|
bin | 1010001100100111111101… |
… | …0010001010101001101100 |
3 | 1110200212010120021011201020 |
4 | 2203021333102022221230 |
5 | 2432144134012024322 |
6 | 35502415521414140 |
7 | 2235016546326315 |
oct | 243117722125154 |
9 | 43625116234636 |
10 | 11212000111212 |
11 | 3632a8984829a |
12 | 1310b6419a350 |
13 | 634396916544 |
14 | 2aa9412a360c |
15 | 1469b33c205c |
hex | a327f48aa6c |
11212000111212 has 24 divisors (see below), whose sum is σ = 26187732544512. Its totient is φ = 3733562091600.
The previous prime is 11212000111201. The next prime is 11212000111223. The reversal of 11212000111212 is 21211100021211.
It is a happy number.
11212000111212 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (11212000111201) and next prime (11212000111223).
It is a junction number, because it is equal to n+sod(n) for n = 11212000111191 and 11212000111200.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 471397464 + ... + 471421247.
It is an arithmetic number, because the mean of its divisors is an integer number (1091155522688).
Almost surely, 211212000111212 is an apocalyptic number.
11212000111212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11212000111212 is an abundant number, since it is smaller than the sum of its proper divisors (14975732433300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11212000111212 is a wasteful number, since it uses less digits than its factorization.
11212000111212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 942819709 (or 942819707 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 15.
Adding to 11212000111212 its reverse (21211100021211), we get a palindrome (32423100132423).
Subtracting 11212000111212 from its reverse (21211100021211), we obtain a palindrome (9999099909999).
The spelling of 11212000111212 in words is "eleven trillion, two hundred twelve billion, one hundred eleven thousand, two hundred twelve".
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