Base | Representation |
---|---|
bin | 11001011111100011111001… |
… | …011000000001101110110000 |
3 | 112200222120100021121101202120 |
4 | 121133203321120001232300 |
5 | 104143433240042320422 |
6 | 1034243115510114240 |
7 | 32421255241310001 |
oct | 3137437130015660 |
9 | 480876307541676 |
10 | 112120010120112 |
11 | 327a7913828525 |
12 | 106a973864b980 |
13 | 4a73b43b54307 |
14 | 1d988cd20d1a8 |
15 | ce67734e445c |
hex | 65f8f9601bb0 |
112120010120112 has 80 divisors (see below), whose sum is σ = 294837501335040. Its totient is φ = 36708686784000.
The previous prime is 112120010120071. The next prime is 112120010120113. The reversal of 112120010120112 is 211021010021211.
It is a happy number.
112120010120112 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 112120010120091 and 112120010120100.
It is not an unprimeable number, because it can be changed into a prime (112120010120113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 86259964 + ... + 87550107.
It is an arithmetic number, because the mean of its divisors is an integer number (3685468766688).
Almost surely, 2112120010120112 is an apocalyptic number.
112120010120112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
112120010120112 is an abundant number, since it is smaller than the sum of its proper divisors (182717491214928).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112120010120112 is a wasteful number, since it uses less digits than its factorization.
112120010120112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173810322 (or 173810316 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 15.
Adding to 112120010120112 its reverse (211021010021211), we get a palindrome (323141020141323).
The spelling of 112120010120112 in words is "one hundred twelve trillion, one hundred twenty billion, ten million, one hundred twenty thousand, one hundred twelve".
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