Base | Representation |
---|---|
bin | 110100001101011011… |
… | …1111011110010101111 |
3 | 101201101211121011021122 |
4 | 1220122313323302233 |
5 | 3314110211121033 |
6 | 123301321051155 |
7 | 11046303306125 |
oct | 1503267736257 |
9 | 351354534248 |
10 | 112120020143 |
11 | 4360591267a |
12 | 19890926abb |
13 | a75a7a73b1 |
14 | 55d89a1915 |
15 | 2db32b6a98 |
hex | 1a1adfbcaf |
112120020143 has 2 divisors, whose sum is σ = 112120020144. Its totient is φ = 112120020142.
The previous prime is 112120020107. The next prime is 112120020149. The reversal of 112120020143 is 341020021211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112120020143 - 28 = 112120019887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112120020149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060010071 + 56060010072.
It is an arithmetic number, because the mean of its divisors is an integer number (56060010072).
Almost surely, 2112120020143 is an apocalyptic number.
112120020143 is a deficient number, since it is larger than the sum of its proper divisors (1).
112120020143 is an equidigital number, since it uses as much as digits as its factorization.
112120020143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 112120020143 its reverse (341020021211), we get a palindrome (453140041354).
The spelling of 112120020143 in words is "one hundred twelve billion, one hundred twenty million, twenty thousand, one hundred forty-three".
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