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11212040103 = 3113110959961
BaseRepresentation
bin10100111000100101…
…00010011110100111
31001221101102122120120
422130102202132213
5140430240240403
65052320533023
7544562524365
oct123422423647
931841378516
1011212040103
1148339a4750
12220aa81173
131098b38c74
14785108635
154594c5e53
hex29c4a27a7

11212040103 has 16 divisors (see below), whose sum is σ = 16834501632. Its totient is φ = 6575976000.

The previous prime is 11212040093. The next prime is 11212040153. The reversal of 11212040103 is 30104021211.

11212040103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11212040103 - 28 = 11212039847 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11212040153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5478958 + ... + 5481003.

It is an arithmetic number, because the mean of its divisors is an integer number (1052156352).

Almost surely, 211212040103 is an apocalyptic number.

11212040103 is a deficient number, since it is larger than the sum of its proper divisors (5622461529).

11212040103 is a wasteful number, since it uses less digits than its factorization.

11212040103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10960006.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 11212040103 its reverse (30104021211), we get a palindrome (41316061314).

The spelling of 11212040103 in words is "eleven billion, two hundred twelve million, forty thousand, one hundred three".

Divisors: 1 3 11 31 33 93 341 1023 10959961 32879883 120559571 339758791 361678713 1019276373 3737346701 11212040103