Base | Representation |
---|---|
bin | 10100111000100101… |
… | …00010011110100111 |
3 | 1001221101102122120120 |
4 | 22130102202132213 |
5 | 140430240240403 |
6 | 5052320533023 |
7 | 544562524365 |
oct | 123422423647 |
9 | 31841378516 |
10 | 11212040103 |
11 | 48339a4750 |
12 | 220aa81173 |
13 | 1098b38c74 |
14 | 785108635 |
15 | 4594c5e53 |
hex | 29c4a27a7 |
11212040103 has 16 divisors (see below), whose sum is σ = 16834501632. Its totient is φ = 6575976000.
The previous prime is 11212040093. The next prime is 11212040153. The reversal of 11212040103 is 30104021211.
11212040103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11212040103 - 28 = 11212039847 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11212040153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5478958 + ... + 5481003.
It is an arithmetic number, because the mean of its divisors is an integer number (1052156352).
Almost surely, 211212040103 is an apocalyptic number.
11212040103 is a deficient number, since it is larger than the sum of its proper divisors (5622461529).
11212040103 is a wasteful number, since it uses less digits than its factorization.
11212040103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10960006.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 11212040103 its reverse (30104021211), we get a palindrome (41316061314).
The spelling of 11212040103 in words is "eleven billion, two hundred twelve million, forty thousand, one hundred three".
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