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1121210001223 = 1386246923171
BaseRepresentation
bin10000010100001101010…
…100101110011101000111
310222012001001102110121121
4100110031110232131013
5121332214230014343
62215024325254411
7144001425522544
oct20241524563507
93865031373547
101121210001223
113a25588a7924
1216136ab64407
1381964069660
143c3a4363bcb
151e272a80aed
hex1050d52e747

1121210001223 has 4 divisors (see below), whose sum is σ = 1207456924408. Its totient is φ = 1034963078040.

The previous prime is 1121210001181. The next prime is 1121210001271. The reversal of 1121210001223 is 3221000121211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1121210001223 - 221 = 1121207904071 is a prime.

It is a super-2 number, since 2×11212100012232 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1121210001197 and 1121210001206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1121210002223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43123461573 + ... + 43123461598.

It is an arithmetic number, because the mean of its divisors is an integer number (301864231102).

Almost surely, 21121210001223 is an apocalyptic number.

1121210001223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1121210001223 is a deficient number, since it is larger than the sum of its proper divisors (86246923185).

1121210001223 is an equidigital number, since it uses as much as digits as its factorization.

1121210001223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86246923184.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1121210001223 its reverse (3221000121211), we get a palindrome (4342210122434).

The spelling of 1121210001223 in words is "one trillion, one hundred twenty-one billion, two hundred ten million, one thousand, two hundred twenty-three".

Divisors: 1 13 86246923171 1121210001223