Base | Representation |
---|---|
bin | 10000010100001101010… |
… | …100110001000111101101 |
3 | 10222012001001110000120222 |
4 | 100110031110301013231 |
5 | 121332214230342031 |
6 | 2215024325421125 |
7 | 144001425566432 |
oct | 20241524610755 |
9 | 3865031400528 |
10 | 1121210012141 |
11 | 3a255890504a |
12 | 16136ab6a7a5 |
13 | 8196407160b |
14 | 3c3a4367b89 |
15 | 1e272a83e7b |
hex | 1050d5311ed |
1121210012141 has 2 divisors, whose sum is σ = 1121210012142. Its totient is φ = 1121210012140.
The previous prime is 1121210012071. The next prime is 1121210012171. The reversal of 1121210012141 is 1412100121211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 770682073225 + 350527938916 = 877885^2 + 592054^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121210012141 - 214 = 1121209995757 is a prime.
It is a super-2 number, since 2×11212100121412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121210012171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560605006070 + 560605006071.
It is an arithmetic number, because the mean of its divisors is an integer number (560605006071).
Almost surely, 21121210012141 is an apocalyptic number.
It is an amenable number.
1121210012141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121210012141 is an equidigital number, since it uses as much as digits as its factorization.
1121210012141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 1121210012141 its reverse (1412100121211), we get a palindrome (2533310133352).
The spelling of 1121210012141 in words is "one trillion, one hundred twenty-one billion, two hundred ten million, twelve thousand, one hundred forty-one".
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