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11212100133 = 313607347339
BaseRepresentation
bin10100111000100101…
…10001001000100101
31001221101112200220220
422130102301020211
5140430244201013
65052322114553
7544563164403
oct123422611045
931841480826
1011212100133
114833a35863
12220aaaba59
131098b5a3a0
14785122473
154594d8b23
hex29c4b1225

11212100133 has 16 divisors (see below), whose sum is σ = 16102416960. Its totient is φ = 6898472064.

The previous prime is 11212100101. The next prime is 11212100143. The reversal of 11212100133 is 33100121211.

It is a happy number.

It is not a de Polignac number, because 11212100133 - 25 = 11212100101 is a prime.

It is a super-2 number, since 2×112121001332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11212100143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 213178 + ... + 260516.

It is an arithmetic number, because the mean of its divisors is an integer number (1006401060).

Almost surely, 211212100133 is an apocalyptic number.

11212100133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11212100133 is a deficient number, since it is larger than the sum of its proper divisors (4890316827).

11212100133 is a wasteful number, since it uses less digits than its factorization.

11212100133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53428.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11212100133 its reverse (33100121211), we get a palindrome (44312221344).

The spelling of 11212100133 in words is "eleven billion, two hundred twelve million, one hundred thousand, one hundred thirty-three".

Divisors: 1 3 13 39 6073 18219 47339 78949 142017 236847 615407 1846221 287489747 862469241 3737366711 11212100133