Base | Representation |
---|---|
bin | 1010001100101000010100… |
… | …1111111110011011010111 |
3 | 1110200212101112121012220222 |
4 | 2203022011033332123113 |
5 | 2432144340122401101 |
6 | 35502433454544555 |
7 | 2235022203141644 |
oct | 243120517763327 |
9 | 43625345535828 |
10 | 11212100200151 |
11 | 363303029a624 |
12 | 1310b9180815b |
13 | 6343b158b676 |
14 | 2aa9506b8dcb |
15 | 1469bc09301b |
hex | a32853fe6d7 |
11212100200151 has 2 divisors, whose sum is σ = 11212100200152. Its totient is φ = 11212100200150.
The previous prime is 11212100200121. The next prime is 11212100200183. The reversal of 11212100200151 is 15100200121211.
It is a weak prime.
It is an emirp because it is prime and its reverse (15100200121211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11212100200151 is a prime.
It is a super-2 number, since 2×112121002001512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212100200111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606050100075 + 5606050100076.
It is an arithmetic number, because the mean of its divisors is an integer number (5606050100076).
Almost surely, 211212100200151 is an apocalyptic number.
11212100200151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212100200151 is an equidigital number, since it uses as much as digits as its factorization.
11212100200151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 11212100200151 its reverse (15100200121211), we get a palindrome (26312300321362).
The spelling of 11212100200151 in words is "eleven trillion, two hundred twelve billion, one hundred million, two hundred thousand, one hundred fifty-one".
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