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11212100200151 is a prime number
BaseRepresentation
bin1010001100101000010100…
…1111111110011011010111
31110200212101112121012220222
42203022011033332123113
52432144340122401101
635502433454544555
72235022203141644
oct243120517763327
943625345535828
1011212100200151
11363303029a624
121310b9180815b
136343b158b676
142aa9506b8dcb
151469bc09301b
hexa32853fe6d7

11212100200151 has 2 divisors, whose sum is σ = 11212100200152. Its totient is φ = 11212100200150.

The previous prime is 11212100200121. The next prime is 11212100200183. The reversal of 11212100200151 is 15100200121211.

It is a weak prime.

It is an emirp because it is prime and its reverse (15100200121211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11212100200151 is a prime.

It is a super-2 number, since 2×112121002001512 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11212100200111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606050100075 + 5606050100076.

It is an arithmetic number, because the mean of its divisors is an integer number (5606050100076).

Almost surely, 211212100200151 is an apocalyptic number.

11212100200151 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212100200151 is an equidigital number, since it uses as much as digits as its factorization.

11212100200151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40, while the sum is 17.

Adding to 11212100200151 its reverse (15100200121211), we get a palindrome (26312300321362).

The spelling of 11212100200151 in words is "eleven trillion, two hundred twelve billion, one hundred million, two hundred thousand, one hundred fifty-one".