Base | Representation |
---|---|
bin | 11001011111100100111010… |
… | …011101010000101110000111 |
3 | 112200222200011101012012211212 |
4 | 121133210322131100232013 |
5 | 104143443004103330041 |
6 | 1034243420113122035 |
7 | 32421324300241103 |
oct | 3137447235205607 |
9 | 480880141165755 |
10 | 112121102011271 |
11 | 327a8324104511 |
12 | 106a99a225931b |
13 | 4a73c89126162 |
14 | 1d9899423a903 |
15 | ce67d92c78eb |
hex | 65f93a750b87 |
112121102011271 has 2 divisors, whose sum is σ = 112121102011272. Its totient is φ = 112121102011270.
The previous prime is 112121102011201. The next prime is 112121102011339. The reversal of 112121102011271 is 172110201121211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112121102011271 is a prime.
It is a super-2 number, since 2×1121211020112712 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112121102011201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060551005635 + 56060551005636.
It is an arithmetic number, because the mean of its divisors is an integer number (56060551005636).
Almost surely, 2112121102011271 is an apocalyptic number.
112121102011271 is a deficient number, since it is larger than the sum of its proper divisors (1).
112121102011271 is an equidigital number, since it uses as much as digits as its factorization.
112121102011271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 23.
Adding to 112121102011271 its reverse (172110201121211), we get a palindrome (284231303132482).
The spelling of 112121102011271 in words is "one hundred twelve trillion, one hundred twenty-one billion, one hundred two million, eleven thousand, two hundred seventy-one".
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