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112121112012 = 223713738231709
BaseRepresentation
bin110100001101011110…
…0000110010111001100
3101201101220122122001020
41220122330012113030
53314111001041022
6123301400314140
711046315504330
oct1503274062714
9351356578036
10112121112012
1143606498a48
1219891172950
13a75aa9a380
1455d8ba77c0
152db343035c
hex1a1af065cc

112121112012 has 192 divisors, whose sum is σ = 326987458560. Its totient is φ = 29112846336.

The previous prime is 112121112007. The next prime is 112121112043. The reversal of 112121112012 is 210211121211.

It is a happy number.

112121112012 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1121211120122 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112121111982 and 112121112000.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 65605414 + ... + 65607122.

It is an arithmetic number, because the mean of its divisors is an integer number (1703059680).

Almost surely, 2112121112012 is an apocalyptic number.

112121112012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112121112012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (163493729280).

112121112012 is an abundant number, since it is smaller than the sum of its proper divisors (214866346548).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112121112012 is a wasteful number, since it uses less digits than its factorization.

112121112012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2632 (or 2630 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 112121112012 its reverse (210211121211), we get a palindrome (322332233223).

The spelling of 112121112012 in words is "one hundred twelve billion, one hundred twenty-one million, one hundred twelve thousand, twelve".