11212113002333 has 4 divisors (see below), whose sum is σ = 11212120421628. Its totient is φ = 11212105583040.

The previous prime is 11212113002221. The next prime is 11212113002351. The reversal of 11212113002333 is 33320031121211.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 10704295714564 + 507817287769 = 3271742^2 + 712613^2 .

It is a cyclic number.

It is not a de Polignac number, because 11212113002333 - 2¹⁸ = 11212112740189 is a prime.

It is a super-2 number, since 2×11212113002333² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11212113002299 and 11212113002308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11212113002933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 540188 + ... + 4766133.

It is an arithmetic number, because the mean of its divisors is an integer number (2803030105407).

Almost surely, 2^{11212113002333} is an apocalyptic number.

It is an amenable number.

11212113002333 is a deficient number, since it is larger than the sum of its proper divisors (7419295).

11212113002333 is an equidigital number, since it uses as much as digits as its factorization.

11212113002333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7419294.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 11212113002333 its reverse (33320031121211), we get a palindrome (44532144123544).

The spelling of 11212113002333 in words is "eleven trillion, two hundred twelve billion, one hundred thirteen million, two thousand, three hundred thirty-three".