Base | Representation |
---|---|
bin | 110100001101011110… |
… | …0001011000100100101 |
3 | 101201101220200121111122 |
4 | 1220122330023010211 |
5 | 3314111002200201 |
6 | 123301400543325 |
7 | 11046315614504 |
oct | 1503274130445 |
9 | 351356617448 |
10 | 112121131301 |
11 | 43606501493 |
12 | 19891181b45 |
13 | a75aaa609a |
14 | 55d8bb083b |
15 | 2db3435e1b |
hex | 1a1af0b125 |
112121131301 has 4 divisors (see below), whose sum is σ = 112479346092. Its totient is φ = 111762916512.
The previous prime is 112121131229. The next prime is 112121131337. The reversal of 112121131301 is 103131121211.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6427870276 + 105693261025 = 80174^2 + 325105^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112121131301 is a prime.
It is a super-2 number, since 2×1121211313012 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 112121131301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112121131901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179106926 + ... + 179107551.
It is an arithmetic number, because the mean of its divisors is an integer number (28119836523).
Almost surely, 2112121131301 is an apocalyptic number.
It is an amenable number.
112121131301 is a deficient number, since it is larger than the sum of its proper divisors (358214791).
112121131301 is an equidigital number, since it uses as much as digits as its factorization.
112121131301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 358214790.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 112121131301 its reverse (103131121211), we get a palindrome (215252252512).
The spelling of 112121131301 in words is "one hundred twelve billion, one hundred twenty-one million, one hundred thirty-one thousand, three hundred one".
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