Base | Representation |
---|---|
bin | 10100111000100101… |
… | …11000011011100111 |
3 | 1001221101121012220221 |
4 | 22130102320123213 |
5 | 140430301130043 |
6 | 5052322505211 |
7 | 544563350503 |
oct | 123422703347 |
9 | 31841535827 |
10 | 11212130023 |
11 | 4833a56266 |
12 | 220ab05207 |
13 | 1098b6ab83 |
14 | 78512d303 |
15 | 4594e28ed |
hex | 29c4b86e7 |
11212130023 has 2 divisors, whose sum is σ = 11212130024. Its totient is φ = 11212130022.
The previous prime is 11212130011. The next prime is 11212130029. The reversal of 11212130023 is 32003121211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11212130023 - 25 = 11212129991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11212129979 and 11212130006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212130029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606065011 + 5606065012.
It is an arithmetic number, because the mean of its divisors is an integer number (5606065012).
Almost surely, 211212130023 is an apocalyptic number.
11212130023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212130023 is an equidigital number, since it uses as much as digits as its factorization.
11212130023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 11212130023 its reverse (32003121211), we get a palindrome (43215251234).
The spelling of 11212130023 in words is "eleven billion, two hundred twelve million, one hundred thirty thousand, twenty-three".
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