Base | Representation |
---|---|
bin | 10100111000100101… |
… | …11011101110110101 |
3 | 1001221101121220110121 |
4 | 22130102323232311 |
5 | 140430302043131 |
6 | 5052323051541 |
7 | 544563435064 |
oct | 123422735665 |
9 | 31841556417 |
10 | 11212143541 |
11 | 4833a65435 |
12 | 220ab10bb1 |
13 | 1098b74081 |
14 | 7851341db |
15 | 4594e6911 |
hex | 29c4bbbb5 |
11212143541 has 2 divisors, whose sum is σ = 11212143542. Its totient is φ = 11212143540.
The previous prime is 11212143533. The next prime is 11212143563. The reversal of 11212143541 is 14534121211.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11099465316 + 112678225 = 105354^2 + 10615^2 .
It is an emirp because it is prime and its reverse (14534121211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11212143541 - 23 = 11212143533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212143571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606071770 + 5606071771.
It is an arithmetic number, because the mean of its divisors is an integer number (5606071771).
Almost surely, 211212143541 is an apocalyptic number.
It is an amenable number.
11212143541 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212143541 is an equidigital number, since it uses as much as digits as its factorization.
11212143541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 960, while the sum is 25.
Adding to 11212143541 its reverse (14534121211), we get a palindrome (25746264752).
The spelling of 11212143541 in words is "eleven billion, two hundred twelve million, one hundred forty-three thousand, five hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •