Base | Representation |
---|---|
bin | 110100001101011111… |
… | …1011111001010001011 |
3 | 101201101222022202011002 |
4 | 1220122333133022023 |
5 | 3314111213000021 |
6 | 123301431325215 |
7 | 11046326163260 |
oct | 1503277371213 |
9 | 351358282132 |
10 | 112122000011 |
11 | 43606a4512a |
12 | 1989152080b |
13 | a75b01b608 |
14 | 55d8d59267 |
15 | 2db355850b |
hex | 1a1afdf28b |
112122000011 has 4 divisors (see below), whose sum is σ = 128139428592. Its totient is φ = 96104571432.
The previous prime is 112121999999. The next prime is 112122000019. The reversal of 112122000011 is 110000221211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112122000011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112121999956 and 112122000001.
It is not an unprimeable number, because it can be changed into a prime (112122000019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8008714280 + ... + 8008714293.
It is an arithmetic number, because the mean of its divisors is an integer number (32034857148).
Almost surely, 2112122000011 is an apocalyptic number.
112122000011 is a deficient number, since it is larger than the sum of its proper divisors (16017428581).
112122000011 is an equidigital number, since it uses as much as digits as its factorization.
112122000011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16017428580.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 112122000011 its reverse (110000221211), we get a palindrome (222122221222).
The spelling of 112122000011 in words is "one hundred twelve billion, one hundred twenty-two million, eleven", and thus it is an aban number.
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