Base | Representation |
---|---|
bin | 11001011111100101110000… |
… | …101000110100001111100100 |
3 | 112200222202111201122010201012 |
4 | 121133211300220310033210 |
5 | 104144001334304310040 |
6 | 1034244050224121352 |
7 | 32421355645506164 |
oct | 3137456050641744 |
9 | 480882451563635 |
10 | 112122011010020 |
11 | 327a8750222750 |
12 | 106a9bb6766258 |
13 | 4a740a255073b |
14 | 1d98a3cc5a5a4 |
15 | ce683ded0865 |
hex | 65f970a343e4 |
112122011010020 has 192 divisors, whose sum is σ = 264016101888000. Its totient is φ = 39644590218240.
The previous prime is 112122011010019. The next prime is 112122011010101. The reversal of 112122011010020 is 20010110221211.
It is a super-2 number, since 2×1121220110100202 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 112122011009977 and 112122011010004.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 10511104727 + ... + 10511115393.
It is an arithmetic number, because the mean of its divisors is an integer number (1375083864000).
Almost surely, 2112122011010020 is an apocalyptic number.
112122011010020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112122011010020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (132008050944000).
112122011010020 is an abundant number, since it is smaller than the sum of its proper divisors (151894090877980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112122011010020 is a wasteful number, since it uses less digits than its factorization.
112122011010020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15618 (or 15616 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 112122011010020 its reverse (20010110221211), we get a palindrome (132132121231231).
It can be divided in two parts, 11212201 and 1010020, that added together give a palindrome (12222221).
The spelling of 112122011010020 in words is "one hundred twelve trillion, one hundred twenty-two billion, eleven million, ten thousand, twenty".
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