Base | Representation |
---|---|
bin | 11001011111100110001000… |
… | …000100100010101010011101 |
3 | 112200222210112010101220212211 |
4 | 121133212020010202222131 |
5 | 104144003140430412023 |
6 | 1034244153230400421 |
7 | 32421401461254451 |
oct | 3137461004425235 |
9 | 480883463356784 |
10 | 112122404154013 |
11 | 327a8932135640 |
12 | 106aa0a6360111 |
13 | 4a74135b31516 |
14 | 1d98a79158661 |
15 | ce686378ca0d |
hex | 65f988122a9d |
112122404154013 has 32 divisors (see below), whose sum is σ = 127953504617472. Its totient is φ = 97253412009600.
The previous prime is 112122404153959. The next prime is 112122404154023. The reversal of 112122404154013 is 310451404221211.
It is a de Polignac number, because none of the positive numbers 2k-112122404154013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112122404154023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 265253370 + ... + 265675732.
It is an arithmetic number, because the mean of its divisors is an integer number (3998547019296).
Almost surely, 2112122404154013 is an apocalyptic number.
It is an amenable number.
112122404154013 is a deficient number, since it is larger than the sum of its proper divisors (15831100463459).
112122404154013 is a wasteful number, since it uses less digits than its factorization.
112122404154013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 425025.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 112122404154013 its reverse (310451404221211), we get a palindrome (422573808375224).
The spelling of 112122404154013 in words is "one hundred twelve trillion, one hundred twenty-two billion, four hundred four million, one hundred fifty-four thousand, thirteen".
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