Base | Representation |
---|---|
bin | 10100111000100110… |
… | …10100010111100111 |
3 | 1001221101211000220011 |
4 | 22130103110113213 |
5 | 140430313310310 |
6 | 5052325151051 |
7 | 544564335226 |
oct | 123423242747 |
9 | 31841730804 |
10 | 11212244455 |
11 | 4834024235 |
12 | 220ab5b487 |
13 | 1098baac99 |
14 | 78515ccbd |
15 | 45951678a |
hex | 29c4d45e7 |
11212244455 has 16 divisors (see below), whose sum is σ = 14064537600. Its totient is φ = 8570558880.
The previous prime is 11212244443. The next prime is 11212244473. The reversal of 11212244455 is 55444221211.
It is not a de Polignac number, because 11212244455 - 29 = 11212243943 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 445585 + ... + 470074.
It is an arithmetic number, because the mean of its divisors is an integer number (879033600).
Almost surely, 211212244455 is an apocalyptic number.
11212244455 is a deficient number, since it is larger than the sum of its proper divisors (2852293145).
11212244455 is an equidigital number, since it uses as much as digits as its factorization.
11212244455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 915774.
The product of its digits is 12800, while the sum is 31.
Adding to 11212244455 its reverse (55444221211), we get a palindrome (66656465666).
The spelling of 11212244455 in words is "eleven billion, two hundred twelve million, two hundred forty-four thousand, four hundred fifty-five".
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