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11212443203 = 13862495631
BaseRepresentation
bin10100111000101000…
…00100111001000011
31001221102012010112012
422130110010321003
5140430341140303
65052333323135
7544566123533
oct123424047103
931842163465
1011212443203
11483414a595
12220b0364ab
131098c4a5a0
147851b14c3
154595555d8
hex29c504e43

11212443203 has 4 divisors (see below), whose sum is σ = 12074938848. Its totient is φ = 10349947560.

The previous prime is 11212443169. The next prime is 11212443269. The reversal of 11212443203 is 30234421211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11212443203 - 28 = 11212442947 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11212493203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431247803 + ... + 431247828.

It is an arithmetic number, because the mean of its divisors is an integer number (3018734712).

Almost surely, 211212443203 is an apocalyptic number.

11212443203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11212443203 is a deficient number, since it is larger than the sum of its proper divisors (862495645).

11212443203 is an equidigital number, since it uses as much as digits as its factorization.

11212443203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 862495644.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11212443203 its reverse (30234421211), we get a palindrome (41446864414).

The spelling of 11212443203 in words is "eleven billion, two hundred twelve million, four hundred forty-three thousand, two hundred three".

Divisors: 1 13 862495631 11212443203