Base | Representation |
---|---|
bin | 11001011111101101001101… |
… | …011111100000000100011010 |
3 | 112201000112011021120222120000 |
4 | 121133231031133200010122 |
5 | 104144114230343100442 |
6 | 1034251452134113430 |
7 | 32422061132035134 |
oct | 3137551537400432 |
9 | 481015137528500 |
10 | 112130011300122 |
11 | 32801086179052 |
12 | 106ab669aab876 |
13 | 4a74a78b658ca |
14 | 1d9919b59c054 |
15 | ce6b5b536d4c |
hex | 65fb4d7e011a |
112130011300122 has 40 divisors (see below), whose sum is σ = 262178383918176. Its totient is φ = 35751597804648.
The previous prime is 112130011300081. The next prime is 112130011300189. The reversal of 112130011300122 is 221003110031211.
112130011300122 is a `hidden beast` number, since 11 + 21 + 300 + 11 + 300 + 1 + 22 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 112130011300095 and 112130011300104.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 15046965048 + ... + 15046972499.
Almost surely, 2112130011300122 is an apocalyptic number.
112130011300122 is an abundant number, since it is smaller than the sum of its proper divisors (150048372618054).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112130011300122 is a wasteful number, since it uses less digits than its factorization.
112130011300122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30093937584 (or 30093937575 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 112130011300122 its reverse (221003110031211), we get a palindrome (333133121331333).
The spelling of 112130011300122 in words is "one hundred twelve trillion, one hundred thirty billion, eleven million, three hundred thousand, one hundred twenty-two".
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