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112130020003 = 234875218261
BaseRepresentation
bin110100001101101111…
…0000101001010100011
3101201102112102012111211
41220123132011022203
53314120241120003
6123302315250551
711046454305211
oct1503336051243
9351375365454
10112130020003
1143610522721
1219894149a57
13a75c898b81
1455da045cb1
152db40de96d
hex1a1b7852a3

112130020003 has 4 divisors (see below), whose sum is σ = 117005238288. Its totient is φ = 107254801720.

The previous prime is 112130020001. The next prime is 112130020069. The reversal of 112130020003 is 300020031211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112130020003 - 21 = 112130020001 is a prime.

It is a super-3 number, since 3×1121300200033 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112130020001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2437609108 + ... + 2437609153.

It is an arithmetic number, because the mean of its divisors is an integer number (29251309572).

Almost surely, 2112130020003 is an apocalyptic number.

112130020003 is a deficient number, since it is larger than the sum of its proper divisors (4875218285).

112130020003 is an equidigital number, since it uses as much as digits as its factorization.

112130020003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4875218284.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 112130020003 its reverse (300020031211), we get a palindrome (412150051214).

The spelling of 112130020003 in words is "one hundred twelve billion, one hundred thirty million, twenty thousand, three".

Divisors: 1 23 4875218261 112130020003