112130020033 has 4 divisors (see below), whose sum is σ = 112152600000. Its totient is φ = 112107440068.

The previous prime is 112130020001. The next prime is 112130020069. The reversal of 112130020033 is 330020031211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112130020033 - 2⁵ = 112130020001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112130019989 and 112130020016.

It is not an unprimeable number, because it can be changed into a prime (112130020433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11282533 + ... + 11292466.

It is an arithmetic number, because the mean of its divisors is an integer number (28038150000).

Almost surely, 2^112130020033 is an apocalyptic number.

It is an amenable number.

112130020033 is a deficient number, since it is larger than the sum of its proper divisors (22579967).

112130020033 is an equidigital number, since it uses as much as digits as its factorization.

112130020033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22579966.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 112130020033 its reverse (330020031211), we get a palindrome (442150051244).

The spelling of 112130020033 in words is "one hundred twelve billion, one hundred thirty million, twenty thousand, thirty-three".