Base | Representation |
---|---|
bin | 110100001101101111… |
… | …0000101001011000010 |
3 | 101201102112102012112222 |
4 | 1220123132011023002 |
5 | 3314120241120114 |
6 | 123302315251042 |
7 | 11046454305254 |
oct | 1503336051302 |
9 | 351375365488 |
10 | 112130020034 |
11 | 4361052274a |
12 | 19894149a82 |
13 | a75c898ba6 |
14 | 55da045cd4 |
15 | 2db40de98e |
hex | 1a1b7852c2 |
112130020034 has 8 divisors (see below), whose sum is σ = 172740841788. Its totient is φ = 54549739440.
The previous prime is 112130020001. The next prime is 112130020069. The reversal of 112130020034 is 430020031211.
It can be written as a sum of positive squares in 2 ways, for example, as 105428141809 + 6701878225 = 324697^2 + 81865^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×1121300200342 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 112130019994 and 112130020021.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 757635197 + ... + 757635344.
Almost surely, 2112130020034 is an apocalyptic number.
112130020034 is a deficient number, since it is larger than the sum of its proper divisors (60610821754).
112130020034 is a wasteful number, since it uses less digits than its factorization.
112130020034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1515270580.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 112130020034 its reverse (430020031211), we get a palindrome (542150051245).
The spelling of 112130020034 in words is "one hundred twelve billion, one hundred thirty million, twenty thousand, thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •