Base | Representation |
---|---|
bin | 110100001101101111… |
… | …0100000000011101101 |
3 | 101201102112121210121121 |
4 | 1220123132200003231 |
5 | 3314120303131112 |
6 | 123302321500541 |
7 | 11046455244313 |
oct | 1503336400355 |
9 | 351375553547 |
10 | 112130130157 |
11 | 43610598461 |
12 | 198941a1751 |
13 | a75c907056 |
14 | 55da0740b3 |
15 | 2db4112407 |
hex | 1a1b7a00ed |
112130130157 has 2 divisors, whose sum is σ = 112130130158. Its totient is φ = 112130130156.
The previous prime is 112130130121. The next prime is 112130130193. The reversal of 112130130157 is 751031031211.
It is a balanced prime because it is at equal distance from previous prime (112130130121) and next prime (112130130193).
It can be written as a sum of positive squares in only one way, i.e., 75101210116 + 37028920041 = 274046^2 + 192429^2 .
It is a cyclic number.
It is not a de Polignac number, because 112130130157 - 231 = 109982646509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112130130107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065065078 + 56065065079.
It is an arithmetic number, because the mean of its divisors is an integer number (56065065079).
Almost surely, 2112130130157 is an apocalyptic number.
It is an amenable number.
112130130157 is a deficient number, since it is larger than the sum of its proper divisors (1).
112130130157 is an equidigital number, since it uses as much as digits as its factorization.
112130130157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 630, while the sum is 25.
Adding to 112130130157 its reverse (751031031211), we get a palindrome (863161161368).
The spelling of 112130130157 in words is "one hundred twelve billion, one hundred thirty million, one hundred thirty thousand, one hundred fifty-seven".
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